3 May
2010
3 May
'10
3:52 p.m.
hi all,
There is attached a document where we see that the particle noise power
is inversely proportional to the receiver radius.
In the previous mail, Max you commented that meausured fluctuations can
be cut down taking as a measure the average value within a time
interval smaller than the correlation time, and you said this
correlation time is equal to the radius of the receiver squared and
divided by the diffusion coefficient, could you explain something else
about how you find this value?
Regards
6 May
6 May
8:27 p.m.
Dear Nora,
In the past days I was working tight on my paper and I did not have the
chance to write a full reply to your email. I'll try to answer to your
questions and add some comments in the following.
Yes, the fluctuations you see are due to the what I call particle counting
noise, meaning that at the receiver, in order to read the concentration,
you're counting the particles inside the spherical boundary for each time
instant. If this number is fluctuating, then you can see fluctuations in the
concentration measure. The particles fluctuate indeed even if the
concentration is kept constant due to the Brownian motion, which makes some
of the particles leave the receptor space or enter the receptor space.
Therefore, for each time instant the number of particles inside the receptor
space is not constant, even if on average (for a concentration kept constant
for infinite time...) the read concentration should be equal to the actual
concentration of particles in the space.
The inverse proportionality of the power of the noise with respect to the
radius of the receiver is indeed right and it matches with the
considerations I did for the particle counting noise. Here you'll find
attached a brief explanation I wrote for the particle counting noise,
including the definition of the correlation time and its application to the
noise power formula.
Please, let me know if you have any comment/suggestion or question on the
things I wrote.
See you all soon,
Max
-----Original Message-----
From: n3-tech-bounces(a)n3cat.upc.edu [mailto:n3-tech-bounces@n3cat.upc.edu]
On Behalf Of garralda(a)ac.upc.edu
Sent: Monday, May 03, 2010 11:53 AM
To: n3-tech(a)n3cat.upc.edu
Subject: [N3-tech] Counting particle noise
hi all,
There is attached a document where we see that the particle noise power is
inversely proportional to the receiver radius.
In the previous mail, Max you commented that meausured fluctuations can be
cut down taking as a measure the average value within a time interval
smaller than the correlation time, and you said this correlation time is
equal to the radius of the receiver squared and divided by the diffusion
coefficient, could you explain something else about how you find this
value?
Regards
7 May
7 May
10:04 a.m.
Hi all,
Thanks Max and Luisca for your insightful comments. Are you available
next Monday at 10 AM for a videoconference? We would discuss Max's noise
findings and the latest simulation results obtained by Nora.
Yours,
Nacho
Al 06/05/2010 22:27, En/na Massimiliano Pierobon ha escrit:
Dear Nora,
In the past days I was working tight on my paper and I did not have the
chance to write a full reply to your email. I'll try to answer to your
questions and add some comments in the following.
Yes, the fluctuations you see are due to the what I call particle counting
noise, meaning that at the receiver, in order to read the concentration,
you're counting the particles inside the spherical boundary for each time
instant. If this number is fluctuating, then you can see fluctuations in the
concentration measure. The particles fluctuate indeed even if the
concentration is kept constant due to the Brownian motion, which makes some
of the particles leave the receptor space or enter the receptor space.
Therefore, for each time instant the number of particles inside the receptor
space is not constant, even if on average (for a concentration kept constant
for infinite time...) the read concentration should be equal to the actual
concentration of particles in the space.
The inverse proportionality of the power of the noise with respect to the
radius of the receiver is indeed right and it matches with the
considerations I did for the particle counting noise. Here you'll find
attached a brief explanation I wrote for the particle counting noise,
including the definition of the correlation time and its application to the
noise power formula.
Please, let me know if you have any comment/suggestion or question on the
things I wrote.
See you all soon,
Max
-----Original Message-----
From: n3-tech-bounces(a)n3cat.upc.edu [mailto:n3-tech-bounces@n3cat.upc.edu]
On Behalf Of garralda(a)ac.upc.edu
Sent: Monday, May 03, 2010 11:53 AM
To: n3-tech(a)n3cat.upc.edu
Subject: [N3-tech] Counting particle noise
hi all,
There is attached a document where we see that the particle noise power is
inversely proportional to the receiver radius.
In the previous mail, Max you commented that meausured fluctuations can be
cut down taking as a measure the average value within a time interval
smaller than the correlation time, and you said this correlation time is
equal to the radius of the receiver squared and divided by the diffusion
coefficient, could you explain something else about how you find this
value?
Regards
_______________________________________________
n3-tech mailing list
n3-tech(a)n3cat.upc.edu
http://mail.n3cat.upc.edu/cgi-bin/mailman/listinfo/n3-tech
3:10 p.m.
Hi All,
Me and Luisca will be available next Monday at 10am for a skype call.
Talk to you on Monday,
Max
From: n3-tech-bounces(a)n3cat.upc.edu [mailto:n3-tech-bounces@n3cat.upc.edu]
On Behalf Of Ignacio Llatser Martí
Sent: Friday, May 07, 2010 6:05 AM
To: n3-tech(a)n3cat.upc.edu
Subject: Re: [N3-tech] Counting particle noise
Hi all,
Thanks Max and Luisca for your insightful comments. Are you available next
Monday at 10 AM for a videoconference? We would discuss Max's noise findings
and the latest simulation results obtained by Nora.
Yours,
Nacho
Al 06/05/2010 22:27, En/na Massimiliano Pierobon ha escrit:
Dear Nora,
In the past days I was working tight on my paper and I did not have the
chance to write a full reply to your email. I'll try to answer to your
questions and add some comments in the following.
Yes, the fluctuations you see are due to the what I call particle counting
noise, meaning that at the receiver, in order to read the concentration,
you're counting the particles inside the spherical boundary for each time
instant. If this number is fluctuating, then you can see fluctuations in the
concentration measure. The particles fluctuate indeed even if the
concentration is kept constant due to the Brownian motion, which makes some
of the particles leave the receptor space or enter the receptor space.
Therefore, for each time instant the number of particles inside the receptor
space is not constant, even if on average (for a concentration kept constant
for infinite time...) the read concentration should be equal to the actual
concentration of particles in the space.
The inverse proportionality of the power of the noise with respect to the
radius of the receiver is indeed right and it matches with the
considerations I did for the particle counting noise. Here you'll find
attached a brief explanation I wrote for the particle counting noise,
including the definition of the correlation time and its application to the
noise power formula.
Please, let me know if you have any comment/suggestion or question on the
things I wrote.
See you all soon,
Max
-----Original Message-----
From: n3-tech-bounces(a)n3cat.upc.edu [mailto:n3-tech-bounces@n3cat.upc.edu]
On Behalf Of garralda(a)ac.upc.edu
Sent: Monday, May 03, 2010 11:53 AM
To: n3-tech(a)n3cat.upc.edu
Subject: [N3-tech] Counting particle noise
hi all,
There is attached a document where we see that the particle noise power is
inversely proportional to the receiver radius.
In the previous mail, Max you commented that meausured fluctuations can be
cut down taking as a measure the average value within a time interval
smaller than the correlation time, and you said this correlation time is
equal to the radius of the receiver squared and divided by the diffusion
coefficient, could you explain something else about how you find this
value?
Regards
_______________________________________________
n3-tech mailing list
n3-tech(a)n3cat.upc.edu
http://mail.n3cat.upc.edu/cgi-bin/mailman/listinfo/n3-tech
5292
days inactive
5296
days old
3 comments
3 participants
participants (3)
-
garralda＠ac.upc.edu -
Ignacio Llatser Martí -
Massimiliano Pierobon